Cos(2x-pi/4)=1/2 решите плиииз

[latex]\cos \left(2x-\dfrac{\pi }{4}\right)=\dfrac{1}{2}\\ 2x-\dfrac{\pi }{4}=-\dfrac{\pi}{3}+2k\pi \vee 2x-\dfrac{\pi }{4}=\dfrac{\pi}{3}+2k\pi\\ 2x-\dfrac{3\pi }{12}=-\dfrac{4\pi}{12}+2k\pi \vee 2x-\dfrac{3\pi }{12}=\dfrac{4\pi}{12}+2k\pi\\ 2x=-\dfrac{\pi}{12}+2k\pi \vee 2x=\dfrac{7\pi}{12}+2k\pi\\ \boxed{x=-\dfrac{\pi}{24}+k\pi \vee x=\dfrac{7\pi}{24}+k\pi}[/latex]