Cos^2x-sin^2x=√3/2 помогите

[latex]cos^2x-sin^2x=\frac{\sqrt3}{2}\\cos2x=\frac{\sqrt3}{2}\\2x=\pm \frac{\pi}{6}+2\pi n\\x=\pm \frac{\pi}{12}+\pi n, \; n\in Z.[/latex]