Дано :m(Zn)=10г HCl. Найти: v=H2

   10г                                                         Х л     Zn       +      2HCl     =     ZnCl2     +    H2n = 1 моль                                          n = 1 мольМ = 65 г/моль                                    Vm = 22,4 л/мольm = 65 г                                             V = 22,4 л10 г Zn      -     Х л Н265 г Zn     -     22,4 л Н2V(H2) = 10 * 22,4 / 65 = 3,4 л