Если (x0,y0) - решение системы (1/5)^2y-x=25 3^y-2x=1/27, то сумма x0+y0 равна

[latex]( \frac{1}{5}) ^{2y-x} =25, \\ (3)^{y-2x}= \frac{1}{27}; \\ ( \frac{1}{5}) ^{2y-x} =( \frac{1}{5} ) ^{-2} , \\ (3 )^{y-2x} =(3) ^{-3} [/latex] [latex] \left \{ {{2y-x=-2} \atop {y-2x=-3}} \right. [/latex] [latex] \left \{ {{-4y+2x=4} \atop {y-2x=-3}} \\ \left \{ {{-3y=1} \atop {2x=y+3}} \\ \left \{ {{y=- \frac{1}{3} } \atop {x= \frac{4}{3} }} \right. [/latex] [latex] x_{o}+y _{o}= \frac{4}{3}- \frac{1}{3} =1 [/latex]