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Гость[latex]\frac{5}{x-y}-\frac{3}{x+y}=\frac{5(x+y)-3(x-y)}{(x+y)(x-y)}=\frac{5x+5y-3x+3y}{(x+y)(x-y)}=\frac{2x+8y}{x^2-y^2}[/latex] /////////////////////////////////////////////////////////////////////////////////////////////////////
Гость[latex]\frac{5x+5y-3x+5y}{(x+y)(x-y)}=\frac{2x+8y}{(x+y)(x-y)}\\ \left \{ {{2x+8y=0 | /2} \atop {(x+y)(x-y)\neq0}} \right.\\ \left \{ {{x+4y=0} \atop {(x+y)(x-y)\neq0}} \right.[/latex]
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