Ответ(ы) на вопрос:
[latex] 5x=2y\quad \Rightarrow \quad \frac{x}{y} =\frac{2}{5} \\\\\frac{x-2y}{3x+y} = \frac{y(\frac{x}{y}-2)}{y(3\cdot \frac{x}{y}+1)} =\frac{\frac{2}{5}-2}{3\cdot \frac{2}{5}+1} = \frac{-\frac{8}{5}}{\frac{11}{5}} = -\frac{8}{11} [/latex]
(x-2y)/(3x+y)=(2x-4y)/(6x+2y)=(2x-10x)/(6x+5x)=(-8/11)x
(x-2y)/(3x+y)=(5x-10y)/(15x+5y)=(2y-10y)/(6y+5y)=(-8/11)y
x-(2y/3x)+y=2x-(4y/6x)+2y=2x-(10x/6x)+5x=8x+(4/6)x
x-(2y/3x)+y=5x-(10y/15x)+5y=2y-(10y/6y)+5y=8y+(4/6)y
Не нашли ответ?
Похожие вопросы