Кто может помочь? прошу

1.3a/15ax;(3a)=1/3x 3y/9y{3};(3y)=1/3y{2} 16a{2}b{4}/48ab{6};(16ab{4})=a/3b{2} 2.3x-3y/6(x-y)=3(x-y)/6(x-y);(3(x-y))=1/2 y{2}+6y+9/6y+18=(y+3){2}/6(y+3);{y+3}=y+3/6 y{2}-25/5y{2}-y{3}=(y-5)(y+5)/y{2}(5-y)=(y-5)(y+5)/-y{2}(y-5);(y-5)=y+5/-y{2} P.S.: ;() -выносим, {} -степень.