[latex] log\sqrt{2}( x^{2} -3x)=4 [/latex] помогите плизз

log2^1/2(x²-3x)=4         ОДЗ   x²-3x>0⇒x(x-3)>02log2(x²-3x)=log2(16)                ____+__0 ___-____3 _+_log2(x²-3x)²=log2(16)(x²-3x)²=16(x²-3x)²-4²=0(x²-3x-4)(x²-3x+4)=0x²-3x-4=0                  x²-3x+4=0D=9+16=25              D=9-16=-7 -корней нетx1=(3+5)/2=4x2=(3-5)/2=-1