[latex] \sqrt{3} sin \frac{x}{4} -cos \frac{x}{4}=0[/latex] [latex]3sin ^{2} x-2sinx*cosx-5cos ^{2} x=0[/latex]
[latex] \sqrt{3} sin \frac{x}{4} -cos \frac{x}{4}=0[/latex]
[latex]3sin ^{2} x-2sinx*cosx-5cos ^{2} x=0[/latex]
Ответ(ы) на вопрос:
[latex] \sqrt{3}sin \frac{x}{4} -cos \frac{x}{4} =0[/latex]
[latex]2( \frac{ \sqrt{3} }{2} sin \frac{x}{4} - \frac{1}{2} cos \frac{x}{4})=0 [/latex]
[latex]\frac{ \sqrt{3} }{2} sin \frac{x}{4} - \frac{1}{2} cos \frac{x}{4}=0[/latex]
[latex] \frac{ \sqrt{3} }{2} =cos \frac{ \pi }{6}, \frac{1}{2} =sin \frac{ \pi }{6} [/latex]
[latex]cos \frac{ \pi }{6}sin \frac{x}{4} -sin \frac{ \pi }{6} cos \frac{x}{4} =0[/latex]
[latex]sin( \frac{x}{4} - \frac{ \pi }{6} )=0[/latex]
[latex] \frac{x}{4} - \frac{ \pi }{6} = \pi k,[/latex] k∈Z
[latex] \frac{x}{4} = \frac{ \pi }{6} +\pi k,[/latex] k∈Z
[latex]x= \frac{2 \pi }{3}+ \frac{ \pi }{4} k,[/latex] k∈Z
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