[latex] \sqrt{35-5x} +2X=9[/latex]

ОДЗ [latex] \left \{ {{35-5x \geq 0} \atop {9-2x \geq 0}} \right. <=> \left \{ {{5x\leq35} \atop {2x \leq 9}} \right.<=> \left \{ {{x\leq7} \atop {x \leq 4,5}} \right.\\\ \\\ (- \infty; 4,5][/latex] [latex]\sqrt{35-5x}+2x=9\\\ \sqrt{35-5x}=9-2x\\\ (\sqrt{35-5x})^2=(9-2x)^2\\\ 35-5x=81-36x+4x^2\\\ 4x^2-31x+46=0\\\ D=961-736=225\\\ x_1=\frac{31+15}{8}=5\frac{3}{4}\\\ x_2=\frac{31-15}{8}=2 [/latex] x₁ не удовлетворяет ОДЗ Ответ 2