[latex] \sqrt{6x^{2} - 3}= \sqrt{5x-2} [/latex]

[latex] ( \sqrt{6 x^{2} -3} )^{2} = (\sqrt{5x-2} )^{2} \\ 6 x^{2} -3x=5x-2 \\ 6 x^{2} -8x+2=0 \\ D= (-8)^{2} -6*4*2=16 \\ x_{1} = \frac{8-4}{2*6} = \frac{1}{3} \\ x_{2} = \frac{8+4}{y=2*6} =1[/latex]