[latex]2 x^{2} -13x+6\ \textless \ 0[/latex] решите неравенство

[latex]2x^2-13x+6\ \textless \ 0 \\Range: x \in R \\Zeros: 2x^2-13x+6=0 \\According\ to\ Vieta's\ theorem: \\ x=6\ or \ x=\frac{1}{2} \\Answer: x\in(\frac{1}{2};6)[/latex]