[latex]3 \frac{3}{4} :(2 \frac{4}{7} -1 \frac{1}{12}) [/latex]

[latex]3\frac{3}{4}:(2\frac{4}{7}-1\frac{1}{12})=\frac{3*4+3}{4}:(\frac{2*7+4}{7}-\frac{1*12+1}{12})=\\\\\frac{15}{4}:(\frac18}{7}-\frac{13}{12})=\\\\\frac{15}{4}:(\frac{18*12-13*7}{7*12}=\\\\\frac{15}{4}:\frac{125}{7*12}=\\\\\frac{15*7*12}{4*125}=\frac{3*7*3}{25}=\frac{63}{25}[/latex]