[latex]x^{2}[/latex]+2x-3=0

x^2 + 2x - 3 = 0 D = b^2-4ac = 2^2 - 4*1*(-3) = 4 + 12 = 16 VD = V16 = 4            -2+4                2 x1 = ------------- = --------- = 1               2                   2                -2-4                 -6 x2 = -------------- = ----------- = -3                2                     2     ответ: x = -3 i x = 1     помогла? поблагодарите!