Lim x--- больше 6 2x 3-2x 2/5x 3-4x 2

[latex]\displaystyle \lim_{n \to \ 6} \frac{2x^3-2x^2}{5x^3-4x^2}= \lim_{n \to \ 6} \frac{2x^2(x-1)}{x^2(5x-4)}= \lim_{n \to \ 6} \frac{2(x-1)}{(5x-4)}= \frac{2(6-1)}{5*6-4}= \frac{5}{13} [/latex]