Lim(1-sinx)/(pi-2x) x- больше pi/2 Решить предел. Пожалуйста!!!!

Lim (1-sinx) / (π -2x)   неопределенность типа 0/0 . x→π/2 * * * * * * * Lim (1-sinx)/(π -2x)=Lim (1-cos(π/2 -x))/(π -2x)=Lim 2sin²(π/4 -x/2)/4(π/4 -x/2) = x→π/2........................x→π/2 ......................................x→π/2 (1/2)Lim sin(π/4 -x/2)/(π/4 -x/2)* Lim sin(π/4 -x/2) =(1/2)*1*0 =0. x→π/2............................................x→π/2 * * * 1 -cosα =2sin²α/2 * * *  1 -sinx =1 - cos(π/2 -x) =2sin²((π/2 -x)/2) =2sin²(π/4 -x/2) .  ===    === Lim (1-sinx)/(π -2x) = Lim (1-cos(π/2 -x)) / 2(π/2 -x) =(1/2)* Lim (1 -cost)/t  = x→π/2........................x→π/2 ....................................................t→0  (1/2)* Lim 2sin²(t/2)/ t  = (1/2)* Lim sin(t/2)/ (t/2) *Lim sint =(1/2)*1*0 =0. t →0............................................t→0......................t→0 || t =π/2 - x⇒ t→0 ,если   x→π/2  ||