Log 7776 по основанию √3

[latex] log_{ \sqrt{3} }7776 = log_{ 3^{ \frac{1}{2} } } 7776=(1: \frac{1}{2} )* log_{3} 7776=2* log_{3} 7776=[/latex] [latex]= log_{3} 7776 ^{2} =2* log_{3} (243*32) =2*( log_{3}243+ log_{3}32 )=[/latex] [latex]=2*(5+ log_{3}32 )=10+2* log_{3}32=10+ log_{3} 32 ^{2} [/latex]