Log (x-3) по основанию 1/3 больше 0

[latex] log_{ \frac{1}{3} } (x-3)\ \textgreater \ 0 0= log_{ \frac{1}{3} } ( \frac{1}{3} ) ^{0}= log_{ \frac{1}{3} } 1[/latex] [latex] log_{ \frac{1}{3} }(x-3)\ \textgreater \ log_{ \frac{1}{3} } 1[/latex] основание логарифма  [latex]a= \frac{1}{3} , 0\ \textless \ \frac{1}{3} \ \textless \ 1[/latex] знак неравенства меняем. [latex] \left \{ {x-3\ \textgreater \ 0} \atop {x-3\ \textless \ 1}} \right., \left \{ {{x\ \textgreater \ 3} \atop {x\ \textless \ 4}} \right. [/latex] x∈(3;4)