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Гостьlog2 x -log2 3=log 2(2x-5) I'm assuming everthing in the above question is to log of base 2. log2 x -log2 3=log2 (2x-5) Apply logarithm law: log a - log b = log (a/b) log2 (x/3) = log2 (2x-5) Remove the log function from both sides of the equation. x/3 = 2x-5
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