(log3 2+3 log0,25):(log3 28-log3 7)

[latex](log_32+3log_30.25):(log_328-log_37)=...[/latex] [latex](log_32+3log_3{\frac14}):log_3\frac{28}{7}=(log_32+log_3{\frac14}^3):log_3\frac{28}{7}=\\=(log_32+log_3{\frac1{64}}):log_3\frac{28}{7}=log_3{\frac2{64}:log_3\frac{28}{7}=\\=log_3{\frac1{32}:log_34=[/latex] [latex]=log_3{\frac1{32}:log_34=log_4\frac1{32}=\log_{2^2}\frac1{2^5}=log_{2^2}2^{-5}=-5*\frac12log_22=[/latex] [latex]=-\frac52=-2.5[/latex]