(log3 2+log2 81 +4)(log3 2-2log18 2)log2 3-log3 2 Подробно пожалуйста

1)log(3)2+log(2)81+4=log(3)2+4/log(3)2+4= =(log²(3)2+4log(3)2+4)/log(3)2=(log(3)2+2)²/log(3)2 2)log(3)2-2log(18)2=log(3)2-2log(3)2/(log(3)2+2)= =(log²(3)2+2log(3)2-2log(3)2)/(2+log(3)2)=log²(3)2/(log(3)2+2) 3)(log²(3)2+2)²/log(3)2 * log²(3)2/(log(3)2+2)*1/log(3)2= =log(3)2+2 4)log(3)2+2-log(3)2=2