Написать первых 7 членов последовательности {Xn=(2n+5)/(3n+8)}

х1=(2*1+5)/3*1+8)=7/11 х2=(2*2+5)/(3*2+8) = 9/14 х3 = (2*3+5)/(3*3+8) = 11/17 х4 = (2*4+5)/(3*4+8) = 13/20 х5 = (2*5+5)/(3*5+8) = 15/23 х6 = (2*6+5)/(3*6+8) = 17/26 х7 = (2*7+5)/(3*7+8) = 19/29