Написать реакцию окисления в водной и кислой среде пентена-1,пентена-2,           2-метилпентена-2

СH2=CH-CH2-CH2-CH3+KMnO4+H2SO4=H-COOH +CH3-CH2-CH2-COOH+MnSO4+ K2SO4+H2O                                                              /   \                                                                                   CO   H2O CH2=CH-CH2-CH2-CH3+KMnO4+H2O=H-COOH + CH3-CH2-CH2-COOH +MnO2+KOH CH3-CH=CH-CH2-CH3 +KMnO4+H2SO4=CH3-COOH +CH3-CH2-COOH+ MnSO4+ K2SO4+H2O CH3-CH=CH-CH2-CH3 +KMnO4+H2O= CH3-COOH + CH3-CH2-COOH +MnO2+KOH CH3-C(CH3)=CH-CH2-CH3+KMnO4+H2SO4=CH3-CH2-COOH +CH3-CO-CH3+K2SO4+ MnSO4+H2O CH3-C(CH3)=CH-CH2-CH3+KMnO4+H2O=CH3-CH2-COOH +CH3-CO-CH3+MnO2+KOH