Найдите корни уравнения 5х \ 4х^2-6 =1

[latex] \frac{5x}{4 x^{2} -6} =1 5x=1*(-(4 x^{2} -6)) 5x=-4x^{2} +6 (4x^{2} - 6) + 5x=0 4x^{2} - 6 + 5x=0 D= b^{2} -4(ac)= 5^{2} -4(-6*4)=25+96=121 x_{1} = \frac{-5+ \sqrt{121} }{8} = \frac{-5+11}{8} = \frac{6}{8} = 3/4=0.75 x_{2} = \frac{-5- \sqrt{121} }{8} = \frac{-5-11}{8} = - \frac{16}{8} =-2 [/latex] Ответ: х=-2; x=0.75.