Найдите корни уравнения x(x-3)(x+1)(x+4)=-35

x(x + 1)(x - 3)(x + 4) = - 35 (x^2 + x)(x^2 + x - 12) = - 35 x^2 + x = t t (t - 12) + 35 = 0  t^2 - 12t + 35 = 0  D = 144 - 35*4 = 4 = 2^2 t1  =( 12 + 2)/2  = 7 t2 = (12 - 2)/2 = 5 #1  x^2 + x = 7 x^2 + x - 7 = 0  D = 1 + 4*7 = 29 x1 = ( - 1 +√29)/2 x2 = ( - 1 - √29)/2 #2 x^2 + x = 5 x^2 + x - 5 = 0  D = 1 + 4*5 = 21 x3 = ( - 1 +√21)/2 x4 = ( - 1 - √21)/2