Найдите наименьший корень уравнения x/(x+3)-4/(x+1)=2

x/(x+3) - 4/(x+1) = 2 x(x+1)/(x+3)(x+1) - 4(x+3) /(x+1)(x+3) = 2 (x(x+1)-4(x+3)) /(x+1)(x+3) = 2 (x²+x-4x-12)/(x+1)(x+3) = 2 (x²-3x-12)/(x²+3x+x+3) = 2 (x²-3x-12)/(x²+4x+3) = 2 (x²-3x-12)/(x²+4x+3) - 2 = 0 (x²-3x-12)/(x²+4x+3) - 2*(x²+4x+3)/(x²+4x+3) = 0 (x²-3x-12)/(x²+4x+3) - (2x²+8x+6)/(x²+4x+3) = 0 (x²-3x-12)-(2x²+8x+6) /(x²+4x+3) = 0 (x²-3x-12-2x²-8x-6)/(x²+4x+3) = 0 (-x²-11x-18)/(x²+4x+3) = 0 |*(x²+4x+3) ОДЗ: (x²+4x+3)≠0 (-x²-11x-18)*(x²+4x+3) = 0 -x²-11x-18=0 |*(-1) x²+11x+18=0 D=121-72= 49 x1,2 = (-11±7)/2 x1= -2   x2= -9 ⇒ -2 - наименьший корень уравнения