Найдите область определения функции:y = [latex] \sqrt[6]{3-x} [/latex] + [latex] \frac{sin x }{ \sqrt[4]{5x-1} } - \sqrt{5 x^{2} -16x + 3 } [/latex]

[latex]y = \sqrt[6]{3-x} + \frac{sin x }{ \sqrt[4]{5x-1} } - \sqrt{5 x^{2} -16x + 3 } [/latex] [latex]3-x \geq 0 \\\ x \leq 3 \\\\ 5x-1>0 \\\ x>0.2 \\\\ 5 x^{2} -16x + 3 \geq 0 \\\ 5 x^{2} -16x + 3 =0 \\\ D_1=64-15=49 \\\ x_1=1.2 \\\ x_2=0.2 \\\ x \leq 0.2; x \geq 1.2[/latex] [latex]x \leq 3 \\\ x>0.2 \\\ x \leq 0.2; x \geq 1.2 \\\\ 1.2 \leq x \leq 3[/latex]