Найдите первый член и знаменатель геометрической прогрессии если ее четвертый член меньше шестого на 8 а пятый больше третьего на 24

[latex] \left \{ {{b_6-b_4=8} \atop {b_5-b_3=24}} \right. [/latex] [latex] \left \{ {{b_1q^5-b_1q^3=8} \atop {b_1q^4-b_1q^2=24}} \right. [/latex] [latex] \left \{ {{b_1q^3(q^2-1)=8} \atop {b_1q^2(q^2-1)=24}} \right. [/latex] [latex] \left \{ {{q*b_1q^2(q^2-1)=8} \atop {b_1q^2(q^2-1)=24}} \right. [/latex] [latex] \left \{ {{q*24=8} \atop {b_1q^2(q^2-1)=24}} \right. [/latex] [latex] \left \{ {{q= \frac{1}{3} } \atop {b_1q^2(q^2-1)=24}} \right. [/latex] [latex] \left \{ {{q= \frac{1}{3} } \atop {b_1( \frac{1}{3})^2 (( \frac{1}{3}) ^2-1)=24}} \right. [/latex] [latex] \left \{ {{q= \frac{1}{3} } \atop { \frac{1}{9} b_1 ( \frac{1}{9}-1)=24}} \right. [/latex] [latex] \left \{ {{q= \frac{1}{3} } \atop { -\frac{8}{81} b_1=24}} \right. [/latex] [latex] \left \{ {{q= \frac{1}{3} } \atop { -\frac{1}{81} b_1=3}} \right. [/latex] [latex] \left \{ {{q= \frac{1}{3} } \atop { b_1=-243}} \right. [/latex] Ответ: [latex]q= \frac{1}{3} } [/latex]; [latex]b_1=-243}} \right. [/latex]