Найдите значение выражения : √2 дробь√18√27*√3 √52 дробь √117решите уравнение:√ из х-1 =3

[latex] \frac{ \sqrt{2} }{ \sqrt{18} } = \sqrt{ \frac{2}{18} }= \sqrt{ \frac{1}{9} } = \frac{1}{3} \\\ \sqrt{27} \cdot\sqrt{3} = \sqrt{27\cdot3} = \sqrt{81} =9 \\\ \frac{ \sqrt{52} }{ \sqrt{117} } = \sqrt{ \frac{52}{117} } = \sqrt{ \frac{4}{9} } = \frac{2}{3} [/latex] [latex] \sqrt{x-1}=3 \\\ x-1=3^2 \\\ x-1=9 \\\ x=10[/latex]

[latex]1)\frac{\sqrt2}{\sqrt{18}}=\frac{\sqrt2}{\sqrt{9*2}}=\frac{\sqrt2}{3\sqrt{2}}=\frac13\\ \\ 2) \sqrt{27}*\sqrt3=\sqrt{9*3}*\sqrt3=3\sqrt3*\sqrt3=3*(\sqrt3)^2=3*3=9\\ \\ 3)\frac{\sqrt{52}}{\sqrt{117}}=\frac{\sqrt{52}}{\sqrt{2.25*52}}=\frac{\sqrt{52}}{1.5\sqrt{52}}=\frac1{1.5}=\frac23\\ \\ 4)\sqrt{x-1}=3\\ x-1=3^2\\ x-1=9\\ x=9+1\\ x=10[/latex]