Найти интеграл dx/(2x^2-11x+2)

[latex]\int\frac{1}{2x^2-11x+2} \ dx = \frac{1}{2}\int\frac{1}{x^2-\frac{11}{2}x+1} \ dx = \frac{1}{2}\int\frac{1}{(x-\frac{11}{4})^2 - \frac{121}{16}+1} \ dx =\\\\\\ \frac{1}{2}\int\frac{1}{(x-\frac{11}{4})^2 - \frac{121}{16}+1} \ dx = \frac{1}{2}\int\frac{1}{(x-\frac{11}{4})^2 - (\frac{\sqrt{105}}{4})^2} \ dx =[/latex]     [latex]\frac{1}{2}\int\frac{1}{(x-\frac{11}{4} - \frac{\sqrt{105}}{4})(x-\frac{11}{4} + \frac{\sqrt{105}}{4})} \ dx = \frac{1}{2}\int\frac{1}{(x - \frac{\sqrt{105} + 11}{4})(x + \frac{\sqrt{105} - 11}{4})} \ dx= [/latex]     [latex]\frac{1}{2}\int\frac{\frac{2}{\sqrt{105}}}{x - \frac{\sqrt{105} + 11}{4}} - \frac{1}{2}\int\frac{\frac{2}{\sqrt{105}}}{x + \frac{\sqrt{105} - 11}{4}} \ dx =\\\\\\ \frac{1}{\sqrt{105}}\int\frac{1}{x - \frac{\sqrt{105} + 11}{4}} \ dx - \frac{1}{\sqrt{105}}\int\frac{1}{x + \frac{\sqrt{105} - 11}{4}} \ dx =[/latex]     [latex]\frac{1}{\sqrt{105}}ln|x - \frac{\sqrt{105} + 11}{4}| - \frac{1}{\sqrt{105}}ln|x + \frac{\sqrt{105} - 11}{4}| + C = [/latex]     [latex]\frac{1}{\sqrt{105}}ln|\frac{x - \frac{\sqrt{105} + 11}{4}}{x + \frac{\sqrt{105} - 11}{4}}| + C =\frac{1}{\sqrt{105}}ln|\frac{4x - \sqrt{105} - 11}{4x + \sqrt{105} - 11}| + C[/latex]