Найти Z из уравнения. (6i+2z)(3-4i)-(20+5 iz)(2-i)=42-31i

[latex]18i-24 i^{2}+6z-8iz-40+20i-10iz+5 i^{2}z-42+31i=0 [/latex] [latex]69i-24 i^{2} +6z-18iz-82+5 i^{2} z=0[/latex] [latex]6z-18iz+5 i^{2} z=-69i+24 i^{2} +82[/latex] [latex]z(6-18i+5 i^{2} )=-69i+24 i^{2} +82[/latex] z=[latex] \frac{24 i^{2}-69i+82 }{5 i^{2}-18i+6 } [/latex]