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[latex] \frac{3}{(2x+1)} + \frac{x}{(2x-1)} = \frac{6}{(4x^2-1)} \\ \\ \frac{3(2x-1)}{(2x+1)(2x-1)} + \frac{x(2x+1)}{(2x-1)(2x+1)} = \frac{6}{(4x^2-1)} \\ \\ \frac{3(2x-1)+x(2x+1)}{(4x^2-1)} = \frac{6}{(4x^2-1)} \\ \\ 3(2x-1)+x(2x+1)=6 \\ \\ 6x-3+2x^2+x-6=0 \\ \\ 2x^2+7x-9=0 \\ D=49-4*2*(-9)=49+72=121 \\ \\ x_{1,2}= \frac{-7б11}{2*2} =1;-4.5[/latex]