Нужна ваша помощь!!Решить системы уравнений: (фото внутри)

:) Пока что первое. Оно очень легкое)

1)[latex] \left \{ {{ x^{2}+2y=2 } \atop {x-y=3}} \right. [/latex] [latex] \left \{ {{ x^{2}+2(x-3)=2} \atop {y=x-3}} \right. [/latex] [latex] \left \{ {{ x^{2}+2x-6=2} \atop {y=x-3}} \right. [/latex] [latex] x^{2} [/latex]+2x-8=0 D=[latex] b^{2} [/latex]-4ac=36 x1=[latex] \frac{-b- \sqrt{D} }{2a} [/latex]=[latex] \frac{-2-6}{2} =-4[/latex] x1=[latex] \frac{-b+ \sqrt{D} }{2a} [/latex]=[latex] \frac{-2+6}{2} =2[/latex] y1=3-(-4)=7 y2=3-2=1 2. [latex] \left \{ {{ 2^{5x+y}= 64^{ \frac{1}{2} } } \atop {3x+2y=-1}} \right. [/latex] [latex] \left \{ {{ 2^{5x+y}=8 } \atop {y=- \frac{1+3x}{2} }} \right. [/latex] [latex] \left \{ {{ 2^{5x- \frac{1+3x}{2}}= 2^{3} } } \atop {y=- \frac{1+3x}{2} }} \right. [/latex] [latex]5x- \frac{1+3x}{2} =3[/latex] [latex] \frac{7x-1}{2} =3[/latex] [latex]7x-1=6[/latex] [latex]7x=7[/latex] [latex]x= \frac{7}{7} =1[/latex] [latex]y=- \frac{1+2}{2} =- \frac{3}{2} [/latex] 3.[latex] \left \{ {{ log_{6}x+ log_{6}y =3 } \atop { 3^{x+y}= (\frac{1}{3}) ^{-13} }} \right. [/latex] [latex] \left \{ {{ log_{6}x+ log_{6}y=3 } \atop { 3^{x+y}= 3^{13} }} \right. [/latex] [latex] \left \{ {{ log_{6}(13-y)+ log_{6}y=3 } \atop {x=13-y}} \right. [/latex] [latex] \left \{ {{ log_{6}(13-y)y=3} \atop {x=13-y}} \right. [/latex] [latex] \left \{ {{ log_{6}13y- y^{2}=3} \atop {x=13-y}} \right. [/latex] [latex] \left \{ {{ 13y- y^{2}= 6^{3} } \atop {x=13-y}} \right. [/latex] [latex] y^{2} -13y+216=0[/latex] [latex]D= b^{2} -4ac=169-4*216\ \textless \ 0 [/latex] -нет корней