Помогите log5 x - 3×logx 5 = 2

log5 x -3/log5 x-2=0 log²5 x-2log5 x -3=0      y=log5 x y²-2y-3=0 D=4+12=16 y1=(2+4)/2=3  log5 x=3     x1=125 y2=(2-4)/2=-1   log5 x =-1   x2=1/5