ПОМОГИТЕ ПОЖАЛУЙСТА!!! 1) [latex] \frac{100}{ \sqrt{11-6 \sqrt{2 } +1} } [/latex] 2)[latex] \frac{ \sqrt{2- \sqrt{3} } }{ \sqrt{2+ \sqrt{3} } } [/latex] 3)(3+2√2)*(1-√2)² 4)[latex] \sqrt{23-4 \sqrt{15} } [/latex] 5) (√a³b-√...

[latex]1) 100/(\sqrt{11-6 \sqrt{2} } +1)=100/( \sqrt{(3- \sqrt{2} )^2} +1)=[/latex][latex]100/(3- \sqrt{2} +1)=100/(4- \sqrt{2} )=100(4+ \sqrt{2} )/(4- \sqrt{2} )(4+ \sqrt{2} )=[/latex][latex]100(4+ \sqrt{2} )/(16-2)=100(4+ \sqrt{2} )/14=50(4+ \sqrt{2} )/7[/latex] [latex]2) \sqrt{2- \sqrt{3} } / \sqrt{2+ \sqrt{3} } = \sqrt{(2- \sqrt{3} )^2} / \sqrt{(2- \sqrt{3})(2+ \sqrt{3} ) }= [/latex][latex](2- \sqrt{3} )/ \sqrt{4-3} =2- \sqrt{3} [/latex] [latex]3)(3+2 \sqrt{2} )(1- \sqrt{2} )^2=(1+ \sqrt{2} )^2*(1- \sqrt{2} )^2=[/latex][latex][(1- \sqrt{2} )(1+ \sqrt{2} )]^2=(1-2)^2=(-1)^2=1[/latex] [latex]4) \sqrt{23-4 \sqrt{15} } = \sqrt{(2 \sqrt{5}- \sqrt{3} )^2 } =2 \sqrt{5} - \sqrt{3} [/latex] [latex]5)( \sqrt{a^3b} - \sqrt{ab} )^2=[ \sqrt{ab} *(a-1)]^2=ab(a-1)^2[/latex] 6 1)2+ √x/(√x +1)=(2√x+2+√x)/(√x +1)=(2+3√x)/(√x +1) 2)(2+3√x)/(√x+1) *3√x(√x+1)/4(3√x+2)=3√x/4