Помогите пожалуйста номер 49 а, в, номер 50 а, в.

№49 а) (8 - 6[latex] \frac{1}{4} [/latex]) * [latex] \frac{1}{4} [/latex]= = 1[latex] \frac{3}{4} [/latex] * [latex] \frac{1}{4} [/latex]= = [latex] \frac{7}{4} [/latex] * [latex] \frac{1}{4} [/latex]= = [latex] \frac{7}{16} [/latex] б) ([latex] \frac{5}{6} [/latex] - [latex] \frac{1}{2} [/latex]) * [latex] \frac{1}{2} [/latex] =  = ([latex] \frac{5}{6} [/latex] - [latex] \frac{3}{6} [/latex]) * [latex] \frac{1}{2} [/latex] = = [latex] \frac{2}{6} [/latex] * [latex] \frac{1}{2} [/latex] = = [latex] \frac{1}{6} [/latex] № 50 а) [latex] \frac{6 - \frac{1}{ \frac{1}{2}- \frac{1}{3}} }{6 + \frac{1}{ \frac{1}{2} - \frac{1}{3}} } = \frac{6 - \frac{1}{ \frac{3}{6} - \frac{2}{6} } }{6 + \frac{1}{ \frac{3}{6} - \frac{2}{3} } } = \frac{6 - \frac{1}{ \frac{1}{6} } }{6 + \frac{1}{ \frac{1}{6} } } = \frac{6 - 6}{6 + 6} = 0[/latex] б) [latex]2 + \frac{1}{1 + \frac{2}{1 + \frac{1}{3} } } = 2 + \frac{1}{1 + \frac{2}{1 \frac{1}{3} } } = 2 + \frac{1}{1 + 1 \frac{1}{2} } = 2 + \frac{1}{2 \frac{1}{2} } = 2 + \frac{1}{ \frac{5}{2} } = 2 + \frac{1}{5} = 2 \frac{1}{5} [/latex] или 2,4