ПОМОГИТЕ пожалуйста решить 2 примера(1,4)!

[latex] \frac{4^{4m-5}*( \frac{1}{6} )^{-2m}}{96^{2m-3}} = \frac{4^{(4m-4)+(-1)}*( \frac{6}{1} )^{2m}}{96^{2m-3}} = \frac{4^{4m-4}*4^{-1}*6^{2m}}{(16*6)^{2m-3}} =[/latex] [latex]=\frac{4^{2(2m-2)}*4^{-1}*6^{2m}}{(16*6)^{2m-3}}=\frac{16^{2m-2}*4^{-1}*6^{2m}}{(16*6)^{2m-3}} =\frac{16^{2m}*6^{2m}*16^{-2}*4^{-1}*6^{2m}}{(16*6)^{2m-3}} =[/latex] [latex]=\frac{(16*6)^{2m}*16^{-2}*4^{-1}}{(16*6)^{2m}*96^{-3}}=\frac{16^{-2}*4^{-1}}{96^{-3}}=\frac{16^{-2}*4^{-1}*96^3}{1}=\frac{(16*6)^3}{16^2*4} =[/latex] [latex]=\frac{16^3*6^3}{16^2*4} = \frac{16^1*36*6}{4} = \frac{4*216}{1} =864[/latex] [latex]\frac{24^{k+1}}{128*4^{k-1}*6^{k-2}}=\frac{24^{k}*24}{128*4^{k}*4^{-1}*6^{k}*6^{-2}}=\frac{24^{k}*24}{4^{k}*6^k*128* \frac{1}{4}* \frac{1}{6^2} }}=\frac{24^{k}*24}{(4*6)^{k}*\frac{128}{4*36}}}=[/latex] [latex]=\frac{(4*6)^{k}*24}{(4*6)^{k}*\frac{4*4*8}{4*4*9}}} =\frac{8*3}{\frac{8}{9}}}= \frac{8*3*9}{8} =3*9=27[/latex]