Помогите, пожалуйста с решением неравенства -2logx/3 27 больше =log3 27x+1

-2*3log(x/3) 3≥log(3) 27+log(3) x +1 -6*log(3) 3/log(3) x-log(3) 3≥3+log(3) x +1 log (3) x=t -6/t-1≥t+4 t+4+6/(t-1)≤0 (t+4)(t-1)+6/t-1≤0 t²+4t-t-4+6/t--1≤0 t²+3t+2/t-1≤0 (t+1)(t+2)/t-1≤0 t≤-2  и  -1≤t<1 log(3) x ≤-2 [latex] \left \{ {{x>0} \atop {x \leq 3^{-2} }} \right. [/latex] [latex] \left \{ {{x>0} \atop {x \leq \frac{1}{9} }} \right. [/latex] 0