Помогите решить: 1) cos(x+п/4)=1 2) sin (3п/2-x)=-1 3) sin(-x)=-0,5 4) tgx/2=корень из 3 5)cos(2x-п/3)=корень из3/2

v 1) x+π/4 =2π*k , k∈ Z . x= - π/4 x+2π*k , k∈ Z . 2) sin(3π/2 -x) = -1; - cosx = -1; cosx  =1; x=2π*k  , k ∈ Z . 3) sin(-x) = -1/2 ; - sinx = -1/2 sinx= 1/2; x= (-1)^(k)*π/6+π*k , k ∈Z. 4) tq(x/2) =√3 ;        [   (tqx)/2 =√3 ]; x/2  = π/3 +π*k , k ∈ Z . x=2π/3 +2π*k , k ∈ Z. 5) cos(2x-π/3) =(√3)/2;  [2x - π/3 =  - π/6 +2π*k ,k ∈ Z  ; 2x - π/3 =   π/6 +2π*k ,k ∈ Z.   [2x = π/3  - π/6 +2π*k ,k ∈ Z  ; 2x = π/3 +  π/6 +2π*k ,k ∈ Z   [2x = π/6 +2π*k ,k ∈ Z  ; 2x = π/2 +2π*k ,k ∈ Z . x = π/12 +π*k ,k ∈ Z  ;  x = π/4 +π*k ,k ∈ Z .