Помогите решить 4целых5/13+(2целых8/13-1целач12/13)+3целых7/13

[latex]4 \frac{5}{13} +(2 \frac{8}{13} -1 \frac{12}{13})+3 \frac{7}{13} = \\ \\ \\ =4 \frac{5}{13} +(1 \frac{21}{13} -1 \frac{12}{13})+3 \frac{7}{13}= \\ \\ \\ =4 \frac{5}{13} + \frac{9}{13} +3 \frac{7}{13}= \\ \\ \\ (4+3)+ \frac{5+9+7}{13} =7 + \frac{21}{13} =7+1 \frac{8}{13} =8 \frac{8}{13} [/latex]