Помогите решить дроби ((121/2-2):(1/5-1/40)-(2+62/3):(15/6-12/3))*3/8 по действиям

1) 121/2 - 2= 60 1/2-2=58 1/2 2) 1/5- 1/40= 8/40-1/40= 7/40 3) 2+62/3= 2+20 2/3= 22 2/3 4) 15/6-12/3= 15/6-22/6= -7/6= -1 1/6 5)58 1/2 : 7/40= 117/2 * 40/7= 117/1 * 20/7= 2340/7 6) 2330/7-22 2/3= 2340/7 -68/3= 7020/21-476/21 = 6544/21 7) 6544/21 : (-1 1/6)= - 6544/21 * 6/7= - 6544/2 * 2=- 13088/7 8) - 13088/7 * 3/8= - 1638/7 *3= - 4908/7= -701 1/7