Помогите решить [latex] 1) x^{2} -5x+6=0; 2) x^{2} +13x+12=0[/latex]

[/latex][latex] x^{2} -5x+6=0[/latex] [latex]D=b^{2} -4ac=(-5)^{2} -4*1*6=25-24=1[/latex] [latex] \sqrt{D} = \sqrt{1} [/latex] [latex] x_{1} = \frac{5+ \sqrt{1} }{2} = \frac{5+1}{2} =3[/latex] [latex] x_{2} = \frac{5-1}{2}=2[/latex] Ответ:3;2 [latex]2) x^{2} +13x+12=0[/latex] [latex]D=b^{2} -4ac=13^{2} -4*1*12=169-48=121[/latex] [latex] \sqrt{D}= \sqrt{121} =11[/latex] [latex] x_{1} = \frac{-13+11}{2} = \frac{-2}{2} =-1[/latex] [latex] x_{2} = \frac{-13-11}{2} = \frac{-24}{2} =-12[/latex] Ответ: -1; -12 .