Помогите решить пожалуйста 10 номер. Буду очень благодарна;)   

10. а) [latex]u^3(v^5u^4)=u^7v^5[/latex] [latex](-cd^8)^6c^7d^5=c^6d^{48}c^7d^5=c^{13}d^{53}[/latex] [latex]-x^5(-3xy^2)^5=-x^5*(-3^5x^5y^{10})=243x^{10}y^{10}[/latex] [latex]5t(-7bt^5)^2=5t*49b^2t^{10}=245b^2t^{11}[/latex] б) [latex](2x^3y)^3(3x^2y^5)^2=8x^9y^3*9x^4y^{10}=72x^{13}y^{13}[/latex] [latex](-a^3c^7)^8(5a^5c^4)^3=a^{24}c^{56}*125a^{15}c^{12}=125a^{39}c^{68}[/latex] [latex](-2u^2z^{11})^2(-uz^3)^8=4u^4z^{22}u^8z^{24}=4u^{12}z^{46}[/latex] в) [latex] \frac{(3xy)^3}{x^2y^5}= \frac{27x^3y^3}{x^2y^5}= \frac{27x}{y^2} \\ \\ [/latex] [latex] \frac{(-2s^2t^3)^5}{(-4st^9)^3}= \frac{-32s^{10}t^{15}}{-64s^3t^{27}}= \frac{s^7}{2t^{12}} [/latex] [latex] \frac{(a^3)^5(d^4)^2}{(-a^2d)^8}= \frac{a^{15}d^8}{a^{16}d^8}= \frac{1}{a} [/latex] [latex] \frac{5w^5(w^2z^3)^4}{(2w^6z)^3}= \frac{5w^5w^8z^{12}}{8w^{18}z^3}= \frac{5z^9}{8w^5} [/latex] [latex] (\frac{(a^3b^2)^4}{a^{11}(b^3)^5} )^4= \frac{(a^{12}b^8)^4}{(a^{11}b^{15})^4}= \frac{a^{48}b^{32}}{a^{44}b^{60}}= \frac{a^4}{b^{28}} [/latex] [latex](- \frac{q^5(t^9)^5}{(qt^{12})^4} )^3=- \frac{(q^5t^{45})^3}{(qt^{48})^3}=- \frac{q^{15}t^{135}}{q^3t^{144}}=- \frac{q^{12}}{t^9} [/latex]