Помогите решить!!! Решите уравнение: [latex]1,2x-0,5x^{2}=4x^{2}-0,8x ; 0,6x^{2}+\sqrt{3}x=0 [/latex];[latex]9 x^{2}-10x=7x^{2}-15x ; \frac{2}{3} x^{2}=5 x [/latex]

1,2x - 0,5x^2 = 4x^2 - 0,8x 2x - 4,5x^2 = 0 45x^2 - 20x = 0 9x^2 - 4x = 0 x(9x - 4) = 0 x =0 or x = 4/9 0,6x^2 + V3x = 0 x(0,6x + V3) = 0 x =0 or x = -5V3/3(V- корень) 9x^2 - 10x = 7x^2 - 15x 2x^2 + 5x = 0 x(2x + 5) = 0 x = 0 x = -2,5 2/3x^2 = 5x 2x^2  - 15x = 0 x(2x - 15) = 0 x = 0 x = 7,5