...Помогите решить : (Сколько сможете) log3(2x-5)=log3(9+2x) lg(x-2)+lg(x+2)=lg(2x-10)

[latex]1)[/latex] [latex] log_{3} (2x-5)= log_{3} (9+2x)[/latex] ОДЗ: [latex] \left \{ {{2x-5\ \textgreater \ 0} \atop {9+2x\ \textgreater \ 0}} \right. [/latex] [latex] \left \{ {{2x\ \textgreater \ 5} \atop {2x\ \textgreater \ -9}} \right. [/latex] [latex] \left \{ {{x\ \textgreater \ 2.5} \atop {x\ \textgreater \ -4.5}} \right. [/latex] [latex]x[/latex] ∈ [latex](2.5;+[/latex] ∞ [latex])[/latex] [latex]2x-5=9+2x[/latex] [latex]0 \neq 14[/latex] Ответ: нет корней [latex]2)[/latex] [latex]lg(x-2)+lg(x+2)=lg(2x-10)[/latex] ОДЗ: [latex] \left \{ {{x-2\ \textgreater \ 0} \atop {x+2\ \textgreater \ 0}}\atop {2x-10\ \textgreater \ 0} \right. [/latex] [latex] \left \{ {{x\ \textgreater \ 2} \atop {x\ \textgreater \ -2}}\atop {x\ \textgreater \ 5} \right. [/latex] [latex]x[/latex] ∈ [latex](5;+[/latex] ∞ [latex])[/latex] [latex]lg[(x-2)(x+2)]=lg(2x-10)[/latex] [latex]lg(x^2-4)=lg(2x-10)[/latex] [latex]x^2-4=2x-10[/latex] [latex]x^2-2x+6=0[/latex] [latex]D=(-2)^2-4*1*6=4-24\ \textless \ 0[/latex] Ответ: нет корней