Помогите решить уравнение 1993= 1+8:(1+8:(1-8:(1+4:(1-4:(1-8:х))))) зарание спасибо

8:(1+8:(1-8:(1+4:(1-4:(1-8х))))) =1993-1 8:(1+8:(1-8:(1+4:(1-4:(1-8х)))) ) =1992 1+8:(1-8:(1+4:(1-4:(1-8х)))) =1/249 8:(1-8:(1+4:(1-4:(1-8х))) =1/249-249/249 8:(8:(1-8:(1+4:(1-4:(1-8х))) =-248/249 1-8:(1+4:(1-4:(1-8х)) =8 * (-249/248) 1-8:(1+4:(1-4:(1-8х)) =-249/31 8:(1+4:(1-4:(1-8х)) =31/31+249/31 8:(1+4:(1-4:(1-8х)) =280/31 1+4:(1-4:(1-8х)) =8*(31/280) 1+4:(1-4:(1-8х)) =31/35 4:(1-4:(1-8х)) =31/35-35/35 4:(1-4:(1-8х)) =-4/35 1-4:(1-8х) =4 * (-35/4) 1-4:(1-8х) =-35 4:(1-8х) =1+35 4:(1-8х) =36 1-8х=1/9 8х=9/9-1/9 8х=8/9 х=1/9 проверка1-8*1/9=1/9 4:1/9=36 1-36=-35 4:(-35)=-4/35 1+(-4/35)=31/35 8:31/35=280/31 1-280/31=-249/31 8/(-249/31)=-248/249 1+(-248/249)=1/249 8:1/249=1992 1+1992=1993 1993=1993