Помогите решить уравнение а) 3/4 m = 57/60 б) 2/5 z + 2/3 z = 16/35

[latex] \frac{3}{4} m= \frac{57}{60} \\ m= \frac{57}{60}: \frac{3}{4} = \frac{57}{60}*\frac{4}{3} = \frac{19}{15} [/latex] [latex] \frac{2}{5} z+ \frac{2}{3} z= \frac{16}{35} \\ z( \frac{2}{5} + \frac{2}{3} )= \frac{16} {35} \\ \frac{2}{5} + \frac{2}{3} = \frac{6+10}{15} = \frac{16}{15} \\ \frac{16}{15}z= \frac{16} {35} \\ z=\frac{16} {35}* \frac{15}{16}= \frac{3}{7} [/latex]