Помогите решить уравнения с помощью дисриминанта: 1.(х+4)(в квадрате)=4х(в квадрате) +5 2.9х(4х-1)=3х-1 3.0,09-4х(в квадрате)=1,6х 4.0,1х(в квадрате) -14= -0,4х 5.(х-4)(4х-3)+3=0 6.(х+5)(в квадрате) + (х-2)(в квадрате) + (х-7)(...

      1)[latex](x+4)^{2}=4x^{2}+5 [/latex] [latex] x^{2}+8x+16=4x^{2}+5 [/latex] [latex] -3x^{2}+8x+11=0 [/latex] D=64+132=196 [latex] x_{1}=\frac{8+\sqrt{196}}{6}=\frac{22}{6}=3\frac{4}{6}=3\frac{2}{3} [/latex] [latex] x_{2}=\frac{8-\sqrt{196}}{6}=\frac{-6}{6}=-1[/latex] 2)[latex]9x(4x-1)=3x-1 [/latex] [latex] 36x^{2}-9x-3x+1=0 [/latex] [latex] 36x^{2}-12x+1=0 [/latex] D=144-144=0 [latex] x_{1}=\frac{12}{2*36}=\frac{12}{72}=\frac{1}{6} [/latex] 3)[latex]0,09-4x^{2}=1,6x [/latex] [latex] -4x^{2}-1,6x+0,09=0 [/latex] D=2,56+1,44=4 [latex] x_{1}=\frac{1,6+\sqrt{4}}{-8}=\frac{3,6}{-8}=-0,45 [/latex] [latex] x_{2}=\frac{1,6-\sqrt{4}}{-8}=\frac{-0,4}{-8}=0,05[/latex]     4) [latex]0,1x^{2}-14=-0,4x [/latex] [latex] 0,1x^{2}+0,4x-14=0 [/latex] D=0,16+5,6=5,76 [latex] x_{1}=\frac{-0,4-\sqrt{5,76}}{0,2}=\frac{-0,4-2,4}{0,2}=\frac{-2,8}{0,2}=-1,4 [/latex] [latex] x_{2}=\frac{-0,4+\sqrt{5,76}}{0,2}=\frac{-0,4+2,4}{0,2}=\frac{2}{0,2}=10[/latex]   5) [latex](x-4)(4x-3)+3=0 [/latex] [latex] 4x^{2}-16x-3x+12+3=0 [/latex] [latex] 4x^{2}-19x+15=0 [/latex] D=361-240=121 [latex] x_{1}=\frac{19+\sqrt{121}}{8}=\frac{30}{8}=\frac{15}{4}=3\frac{3}{4} [/latex] [latex]  x_{2}=\frac{19-\sqrt{121}}{8}=\frac{8}{8}=1[/latex] 6)[latex](x+5)^{2}+(x-2)^{2}+(x-7)(x+7)=11x+80 [/latex] [latex] x^{2}+10x+25+x^{2}-4x+4+x^{2}-49+11x-80=0 [/latex] [latex] 3x^{2}-5x-100=0 [/latex] D=25+1200=1225 [latex] x_{1}=\frac{5+\sqrt{1225}}{6}=\frac{40}{6}=\frac{20}{3}=6\frac{2}{3} [/latex] [latex] x_{2}=\frac{5-\sqrt{1225}}{6}=\frac{-30}{6}=-6[/latex]