Помогите с логарифмами, пожалуйста! Те, которые обведены

231 (log²²(2)3+log(2)9*log(2)5-3log²²(2)5)/(log(2)3+3log(2)5)= =(log(2)3+3log(2)5)*(log(2)3-log(2)5)/(log(2)3+3log(2)5)= =log(2)3-log(2)5=log(2)0,6 232 (log(2)√5-log(∛4)5+log(4)25-1/log(5)2)²-log²(2)2/5= =(1/2*log(2)5-3/2*log(2)5+log(2)5-log(2)5)²-log²(2)2/5= =(-log(5)5)²-log²(2)2/5=log²(2)5-log²(2)2/5= =(log(2)5-log(2)2/5)*(log(2)5+log(2)2/5)=log(2)25/2*log(2)2= =(log(2)25-log(2)2)*1=2log(2)5 -1