Помогите сделать!log(x)2-log(4)X=7/6

logx_2 - 1/2* log2_x = 7/6; 1/ log2_x - 1/2* log2_x = 7/6; log2_x = t; 1 / t - 1/2  * t - 7/6 = 0; 6 - 3 t^2 - 7 t = 0; 3 t^2 + 7t - 6 = 0; D = 49 + 72 = 121= 11^2; t1 = - 6; ⇒log2_x = 6;   x = 2^6 = 64; t2 = 2/3;  ⇒ log2_x = 2/3; x = 2^(2/3)= 4^(1/3)=корень кубический из 4